
Trig Integrals
can I have some help with this problem:
integrate x^2 sin x^3 dx from 0 to 1
http://www3.wolframalpha.com/Calcula...=48&w=269&h=36although I do not know that it equals 0.153233, that just what wolfram says
the integral should equal:
http://www3.wolframalpha.com/Calcula...&s=6&w=72&h=36
but now I am not sure how to use the 'from 0 to 1' in this. I thought that it would be something like:
http://www3.wolframalpha.com/Calcula...=35&w=237&h=36
could someone please help clarify?

Re: Trig Integrals
Forget the bounds for now, consider only the indefinite integral.
We may substitute $\displaystyle u = x^3$, in which $\displaystyle du = 3x^2 dx \Rightarrow \frac{1}{3}du = x^2 dx$. You should be able to substitute and evaluate the new integral. Remember to backsubstitute and then substitute the bounds.