I worked out my solution and was hoping for some input from the experts as to whether I did this correctly or not.
Thanks in advance!!
Compute the indicated derivative.
f'''(t) for f(t) = 4t^{2} - 12 + (4/t^{2})
F’(t) = (d/dt) (4t^{2} -12 + (4/t^{2})
= 8t + 4t^{-2}
F’’(t) = (d/dt) (8t + 4t^{-2})
= 8 – 8t^{-1}
F’’’(t) = (d/dt) (8 – 8t^{-1})
= 8
Okay, so lets see if I understand this now...., lets use the following:
Find the derivative:
f(x) = (x^3/2 - 4x) (x^4 - 3/x^2 +2)
then I would rewrite as........
= (x^3/2 -4x) (x^4 - 3x^-2 + 2)
then, take the derivative.......
f ' (x) = [((3/2 x^-3/2) - 4)(x^4 - 3x^-2 +2)] + [(x^3/2 - 4x) (4x^2 + 3x^-3)]
Ive got a headache now, btw
Not quite, though the errrors may be typos. The derivative of x^(3/2) is (3/2)x^(3/2- 1)= (3/2)x^(1/2), not (3/2)x^(-3/2),
the derivative of x^4 is 4x^(4- 1)= 4x^3, not 4x^2, and the derivative of 3x^(-2) is 3(-2)x^(-2-1)= -6x^(-3), not 3x^(-3).
Don't worry, you'll get used to it!Ive got a headache now, btw