# Need help with integration (questions with fractions, and e)

• November 13th 2012, 02:29 AM
EarlyTravel
Need help with integration (questions with fractions, and e)
Hi, I can do basic integration but on stuck on a few questions, with fractions and e. If you show me how to do these two, I'm sure I could do the rest.

1. http://i47.tinypic.com/kx93n.png dx

2. http://i48.tinypic.com/15gaac.png dx

Thanks, really appreciate any input.
• November 13th 2012, 03:43 AM
darthjavier
Re: Need help with integration (questions with fractions, and e)
Hello

1. $\mathrm{\displaystyle\int\dfrac{1}{4x+1}dx=\dfrac{ \ln(4x+1)}{4}+C}$

$\boxed{\mathrm{\displaystyle\int\dfrac{dt}{t}=\ln t+C}}$

2. $\mathrm{\displaystyle\int4e^{1-4x}=-e^{1-4x}+C}$

$\boxed{\mathrm{\displaystyle\int e^t=e^t+C}}$

Greetings :)
• November 13th 2012, 03:56 AM
Prove It
Re: Need help with integration (questions with fractions, and e)
Quote:

Originally Posted by darthjavier
Hello

1. $\mathrm{\displaystyle\int\dfrac{1}{4x+1}dx=\dfrac{ \ln(4x+1)}{4}+C}$

$\boxed{\mathrm{\displaystyle\int\dfrac{dt}{t}=\ln t+C}}$

2. $\mathrm{\displaystyle\int4e^{1-4x}=-e^{1-4x}+C}$

$\boxed{\mathrm{\displaystyle\int e^t=e^t+C}}$

Greetings :)

No, the first is incorrect. It should be \displaystyle \begin{align*} \int{\frac{1}{4x + 1}\,dx} = \frac{\ln{|4x + 1|}}{4} + C \end{align*} since \displaystyle \begin{align*} \int{\frac{1}{t}\,dt} = \ln{|t|} + C \end{align*}.
• November 13th 2012, 06:12 AM
darthjavier
Re: Need help with integration (questions with fractions, and e)
Quote:

Originally Posted by Prove It
No, the first is incorrect. It should be \displaystyle \begin{align*} \int{\frac{1}{4x + 1}\,dx} = \frac{\ln{|4x + 1|}}{4} + C \end{align*} since \displaystyle \begin{align*} \int{\frac{1}{t}\,dt} = \ln{|t|} + C \end{align*}.

Oops I'm sorry :P