I have this question 1. Solve the following DE’s, by inspection. y’= -sin x
I Know that y=cos x and y'= -sin x. Then is y=cos x the answer? What does it mean when solve by inspection???
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Solving by inspection involves exactly what you did (well, almost, you forgot the constant of integration)...you know that: and so we must have:
Oh thanks for the reply!
Then let's say for y'' = 3 and I did. y'=3x+c
y= (3/2)x^2 +C
Then is y= (3/2)x^2 + C answer for y"=3?
No, for the second example, you should observe that: hence:
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