find the volume of the solid obtained by rotating the region bounded by: y=x^3, y=8, x=0 about the y-axis
I drew the graph up it the attachments. Im using tube method to solve this ∫ 2*pi*r*h, so for me it will be integral from 2 to 0 ∫ 2*pi*x*8 from that i get 32pi. And the answer is (96pi)/5.
Can some please help out im not sure what the problem is really, or i must be missing some small, please look at the attachment of the graph for it.
Thanks in advance