T^4= (16Pi^4)/5 + 16∑{n=1, ∞}[((2Pi^2)/n^2 ) - (3/n^4)] Cos[nt] + 16 Pi ∑{n=1,∞} ((3/n^3)-(Pi^2/n))Sin[nt]

From the fourier series above deduce the summations

∑{n=1,∞} (1/n^4) = (Pi^4)/90 ; ∑{n=1,∞} ((-1)^n+1)/n^4= (7Pi^4)/720

∑{n=odd} 1/n^4 = (Pi^4)/96

I do not understand what I am being asked to do with the problem. Do I need to find a value for t to figure this out? Any help would be appricated. Thank you for your time.