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Math Help - Using inverse laplace of F(s)/(s-a)

  1. #1
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    Using inverse laplace of F(s)/(s-a)

    Hi,
    I have a function in the Laplace domain, and I want to tranform it to the time domain.

    C(s)=(1/V)A(s)/(s - k)
    Using A(s)/s \leftrightarrow \int A(\tau)d\tau, and the shift property, I get

    C(t) = 1/V \int e^{k\tau} A(\tau) d\tau

    But this is wrong as it should become a convolution integral.

    Thanks for any input.
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  2. #2
    MHF Contributor
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    Re: Using inverse laplace of F(s)/(s-a)

    Hey algorithm.

    You should try using the convolution algorithm and consider F(s) = A(s) and G(s) = 1/(s-k) and find L^(-1){F(s)G(s)} using the convolution theorem (assuming V is a constant).
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