Thread: Using inverse laplace of F(s)/(s-a)

Hi,
I have a function in the Laplace domain, and I want to tranform it to the time domain.


Using , and the shift property, I get



But this is wrong as it should become a convolution integral.

Thanks for any input.

Hey algorithm.

You should try using the convolution algorithm and consider F(s) = A(s) and G(s) = 1/(s-k) and find L^(-1){F(s)G(s)} using the convolution theorem (assuming V is a constant).