Using inverse laplace of F(s)/(s-a)

Hi,

I have a function in the Laplace domain, and I want to tranform it to the time domain.

$\displaystyle C(s)=(1/V)A(s)/(s - k)$

Using $\displaystyle A(s)/s \leftrightarrow \int A(\tau)d\tau$, and the shift property, I get

$\displaystyle C(t) = 1/V \int e^{k\tau} A(\tau) d\tau$

But this is wrong as it should become a convolution integral.

Thanks for any input.

Re: Using inverse laplace of F(s)/(s-a)

Hey algorithm.

You should try using the convolution algorithm and consider F(s) = A(s) and G(s) = 1/(s-k) and find L^(-1){F(s)G(s)} using the convolution theorem (assuming V is a constant).