imgur: the simple image sharer

for the first one,

i tried:

let e^x = u

du/dx = e^x

but then i couldn't put that back in (du = e^x dx is of no use)

then I tried let

e^2x = u

du = 2e^2x dx

putting it back in i had

1/2 Integral of [ ucos(u^1/2)du ]

let f = u let dg/du = cos(u^1/2)

df/du = 1 g = ?? Got ugly here i think.

Any ideas?