Thread: integrate this by parts and substitution

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for the first one,
i tried:

let e^x = u
du/dx = e^x
but then i couldn't put that back in (du = e^x dx is of no use)

then I tried let
e^2x = u

du = 2e^2x dx
putting it back in i had

1/2 Integral of [ ucos(u^1/2)du ]

let f = u let dg/du = cos(u^1/2)
df/du = 1 g = ?? Got ugly here i think.
Any ideas?

Hey 99.95.

Use the hint that e^x*e^x = e^2x where du = e^xdx and u = e^x.

Your first substitution attempt would give you:

and your integral becomes:



Now try integration by parts.

Thanks guys, got it!

Could I get some help for the second one? I'm quite bewildered

Let:

and the integral becomes:



Now use integration by parts.

Try introducing a SQRT(x)*SQRT(x) term and just check that this is OK for the integral (it should be, but you'll need to check for yourself just in case). So instead of finding e^(SQRT(x))dx find SQRT(x)e^(SQRT(x))/SQRT(x)dx (Also this should work because you only have a single point where this breaks down which means it should be OK).