$\displaystyle \lim_{x \to -\infty } \frac{\sqrt{2x^2 + 1}}{3x - 5}\\\lim_{x \to -\infty } \frac{(\sqrt{2x^2 + 1}) \cdot \frac{1}{\sqrt{x^2}}}{(3x - 5) \cdot \frac{1}{x}}\\= \frac{\sqrt{2}}{3}$

But the solution says it's negative. Why is it negative? Is it just because the limit is going to negative infinity? So every time I take a limit going to negative infinity, should I just make my answer negative?