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Hello MHF, i hv a new problemn, the question is:
knowing that 2y+4x-6=0 is the equation which is one of the lines tangent to the curve y= 2x^3-x^2+cx+d.
Find the derivative of this function in one of the points of the curve.
How can i find the common point?
Rewrite the tangent lineas
, so you can see that the tangent line has gradient = -2.
This means the derivative of your curve must be -2. So take the derivative, set it equal to -2, solve for x, then substitute this value into the equation for the curve to find y.
But now how can i find the value of "C"?
Quote:
Originally Posted by Prove It
Rewrite the tangent line
This means the derivative of your curve must be -2. So take the derivative, set it equal to -2, solve for x, then substitute this value into the equation for the curve to find y.
You don't need to find the value of c. It is a parameter. Your point of tangency will be in terms of c and d.
This would be my X??Quote:
Originally Posted by Prove It
and