Given a function g, continue to any x in R : g(1)=5 and the Integral of g(t)dt=2 in {0,1} If f(x)=1/2(Integral of(x-t)^2)g(t)dt) in {0,x} Prube that f'(x)=x(integral(g(t)dt- t·g(t)dt) in {0,x} then find f''(1) and f'''(1)
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Hey nigromante. Can you show us what you have tried (partial attempts are OK) as well as any ideas you have to solve the problem? Hint: Use the fundamental theorem of calculus to link f(x) with f'(x).
Nailed it, I know this threads been dead, but I got stuck on it at first glance:
THanks, I get the same, but now I have a problem with the third derivate, on the second I get: f''(1)=Integrate of g(t)dt, {0,1}=2, but f'''(1) I think is zero, but it supose to be "5".
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