Re: Related rates problem

Also I forgot to add in the Chain Rule for the differentiation, so there should be a dtheta/dt added onto that second term. But we already know that value so the problem is still finding the y.

Re: Related rates problem

$\displaystyle \cot{\theta} = \frac{y}{5}$

$\displaystyle -\csc^2{\theta} \cdot \frac{d\theta}{dt} = \frac{1}{5} \cdot \frac{dy}{dt}$

$\displaystyle -5\csc^2{\theta} \cdot \frac{d\theta}{dt} = \frac{dy}{dt}$

plug and chug the left side and evaluate $\displaystyle \frac{dy}{dt}$