Express the area of the given surface as an interated double integral in polar coordinates, and then find the surface area.
A) the portion of the cone z=sqrt(x2+y2) That lies inside the cylinder x2+y2=2x
First thing I did was transform x2+y2=2x into polar coords and got
So I pretty much guessed that the integral goes from 0≤r≤2cos
and also guessed that theta went from 0≤theta≤pi/2
Not really sure how to prove that is goes from theta to pi/2 just assumed it was in quardrant 1.
Now here is where I get confused,
I then got the partials of z2=x2+y2 doing so I got
I plug it into the formula for surface area which is sqrt[(dz/dx)2+ (dz/dy)2+1]da and im pretty sure this is incorrect.
Thanks for the help