# Thread: determining the equation of tangent line given ex^2x at x=1

1. ## determining the equation of tangent line given ex^2x at x=1

the function is $f(x)=xe^2x$

find equation of tangent line at x=1

this is what I did

$f'(x)=x*(e^2x)*2 + e^2x$

$f'(1)=3*e^2$

so the equation of tangent line is

$y=3x*e^2$

is this correct?

2. ## Re: determining the equation of tangent line given ex^2x at x=1

First, a LaTeX tip: if your exponent contains more than 1 character, enclose it within braces, e.g., e^{2x}

You have correctly found $f'(1)$, now for the tangent line, you want to use the point-slope formula:

$y-f(1)=f'(1)(x-1)$

3. ## Re: determining the equation of tangent line given ex^2x at x=1

test to see if I got the code right for TEX

Originally Posted by kingsolomonsgrave
the function is $f(x)=xe^{2x}$

find equation of tangent line at x=1

this is what I did

$f'(x)=x*(e^{2x})*2 + e^{2x}$

$f'(1)=3*e^2$

so the equation of tangent line is

$y=3x*e^2$

is this correct?