I am not too sure how to go about the question 'integrate xlnx dx'
the answer is meant to be (x^2lnx)/2-x^2/4+C
could someone help please?
Follow Math Help Forum on Facebook and Google+
Use integration by parts. Let:
Oh, ok!! I think I had messed up the 'u', 'du', 'dv' and 'dv' before.
Thank you so much for your help
when integrating -x^2(1/x dx), why does 2 become a numerator (e.g. (2-x^2)/4)
I'm not sure what you are asking, but:
Usually integration by parts with lnx and some polynomial term in x, you use lnx term to be u, so that, differentiating it cancels other term (more of an exam tip).
Salahuddin Maths online
I use the LIATE mnemonic to determine which should be u.
View Tag Cloud