Thread: Limit when x goes to infinity.

I'm not completely sure if this goes under calculus or not (Norwegian system is a bit different)

Anyway, i was wondering if anyone could explain the methodology for solving this limit, as you see the answer should be 2, but i'm not getting that.

http://www3.wolframalpha.com/Calcula...s=4&w=130&h=40

And once i wrote it out it became more obvious, divide numerator and denominator by 3^(5x), then x-> unlimited, (2 + 0) / (1 + 0)

Yes, that is correct.