f(x) = 9sin(cos(x^6))

I think im supposed to use the chain rule here but not sure how.

Printable View

- Oct 14th 2007, 07:27 PMpseizure2000Last differential question. Trig inside a trig.
f(x) = 9sin(cos(x^6))

I think im supposed to use the chain rule here but not sure how. - Oct 14th 2007, 07:48 PMKrizalid
$\displaystyle f(x)=9\sin(\cos x^6)\implies f'(x)=9\cos(\cos x^6)\cdot(\cos x^6)'$

Can you take it from there? - Oct 14th 2007, 07:53 PMpseizure2000
yes yes. thank you very much. i really need to study this mess.