f(x)=(x^4+1)^(sinx) Can somebody show me the steps?
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Originally Posted by littleblackdress f(x)=(x^4+1)^(sinx) Can somebody show me the steps? Logarithmic Differentiation
Originally Posted by littleblackdress f(x)=(x^4+1)^(sinx) Can somebody show me the steps? y=(x^4+1)^(sinx) ln(y) =ln((x^4+1)^(sinx) =(sinx)ln(x^4+1) d/dx(lny)=d/dx((sinx)ln(x^4+1)) (1/y)y'=(sinx)((4x^3)/(x^4+1))+((cosx)ln(x^4+1)) now solve for y' (You already know your y which is y=(x^4+1)^(sinx) ) f '(x)=y '
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