Attachment 25388
What is going on in the last two steps?
Is it that 2x must be the value that makes sin theta = sqrt(3)/2 and so it must be pi/3 or 2pi/3 or even integer multiples thereof and the second step we divide by two to get x?
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Attachment 25388
What is going on in the last two steps?
Is it that 2x must be the value that makes sin theta = sqrt(3)/2 and so it must be pi/3 or 2pi/3 or even integer multiples thereof and the second step we divide by two to get x?
Yes, that's what happens.
Letthen we obtain the equation
We have two different solutions now:
which gives us (if we divide both sides by 2)
where
