Attachment 25388

What is going on in the last two steps?

Is it that 2x must be the value that makes sin theta = sqrt(3)/2 and so it must be pi/3 or 2pi/3 or even integer multiples thereof and the second step we divide by two to get x?

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- Oct 24th 2012, 09:12 AMkingsolomonsgravefinding horizontal tangents using d/dx of trigs
Attachment 25388

What is going on in the last two steps?

Is it that 2x must be the value that makes sin theta = sqrt(3)/2 and so it must be pi/3 or 2pi/3 or even integer multiples thereof and the second step we divide by two to get x? - Oct 24th 2012, 10:29 AMSironRe: finding horizontal tangents using d/dx of trigs
Yes, that's what happens.

Let then we obtain the equation

We have two different solutions now:

which gives us (if we divide both sides by 2)

where