This problem is giving me, well...problems: 2x^2 tan(x) -------------- = f(x) sec (x) not sure how im supposed to differentiate this at all.
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Originally Posted by pseizure2000 2x^2 tan(x) -------------- = f(x) sec (x) $\displaystyle \frac{\tan x}{\sec x}=\sin x,$ therefore it remains to differentiate $\displaystyle f(x)=2x^2\sin x$ Does that make sense?
Originally Posted by pseizure2000 This problem is giving me, well...problems: 2x^2 tan(x) -------------- = f(x) sec (x) not sure how im supposed to differentiate this at all. $\displaystyle \frac{\tan x}{\sec x} = \frac{\sin x / \cos x}{1/\cos x} = \sin x$. Thus we have, $\displaystyle 2x^2\sin x$. Which is simpler. This is Mine 73th Post!!!
thanks didn't catch that at all!
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