Results 1 to 3 of 3
Like Tree1Thanks
  • 1 Post By Soroban

Math Help - can someone explain this step (from implicit differentiation question)

  1. #1
    Member
    Joined
    May 2012
    From
    Toronto
    Posts
    244
    Thanks
    1

    can someone explain this step (from implicit differentiation question)

    can someone explain this step (from implicit differentiation question)-screen-shot-2012-10-24-12.08.01-pm.png

    I'm not sure how the numerator became 12x^3/2 -1
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member

    Joined
    May 2006
    From
    Lexington, MA (USA)
    Posts
    11,738
    Thanks
    644

    Re: can someone explain this step (from implicit differentiation question)

    Hello, kingsolomonsgrave!

    \frac{dy}{dx} \;=\;\frac{6x-\frac{1}{2}x^{-\frac{1}{2}}}{\sin(y)} \quad\Rightarrow\quad \frac{dy}{dx} \;=\; \frac{12x^{\frac{3}{2}}-1}{2\sqrt{x}\sin(y)}\quad\text{How?}

    We have: . \frac{6x-\frac{1}{2}x^{-\frac{1}{2}}}{\sin(y)}

    Multiply by \frac{2x^{\frac{1}{2}}}{2x^{\frac{1}{2}}}\!:\;\; \frac{2x^{\frac{1}{2}}}{2x^{\frac{1}{2}}}\cdot \frac{6x-\frac{1}{2}x^{-\frac{1}{2}}}{\sin(y)}  \;=\;\frac{12x^{\frac{3}{2}} - 1}{2x^{\frac{1}{2}}\sin(y)}
    Thanks from kingsolomonsgrave
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Member
    Joined
    May 2012
    From
    Toronto
    Posts
    244
    Thanks
    1

    Re: can someone explain this step (from implicit differentiation question)

    thanks! we know to choose 2x^1/2/2x^1/2 because that will make the 1/2x^-1/2 equal to 1?
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 1
    Last Post: October 17th 2012, 08:01 AM
  2. kindly explain the step
    Posted in the Algebra Forum
    Replies: 9
    Last Post: July 9th 2011, 12:55 AM
  3. Please explain this step
    Posted in the Algebra Forum
    Replies: 2
    Last Post: February 26th 2010, 07:53 AM
  4. Replies: 4
    Last Post: April 4th 2009, 07:32 PM
  5. Please explain step by step
    Posted in the Algebra Forum
    Replies: 5
    Last Post: October 8th 2007, 09:48 AM

Search Tags


/mathhelpforum @mathhelpforum