# Math Help - Alternating Series test

1. ## Alternating Series test

sin[(2n-1)pi]/2

2. ## Re: Alternating Series test

Do you really need to use the alternating series test here? You should know that \displaystyle \begin{align*} \sin{\left[ \frac{\left( 2n - 1 \right) \pi}{2} \right]} = (-1)^{n + 1} \end{align*}, and so adding them, the series can't possibly converge because it can only ever take the values of 1 and 0.