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Math Help - after implicitly differentiating an expression, find equation of tangent line at x=a

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    after implicitly differentiating an expression, find equation of tangent line at x=a

    after implicitly differentiating an expression,  find equation of tangent line at x=a-screen-shot-2012-10-23-7.50.11-pm.png

    I differentiated x^2+y=xy to get the above equation.

    Then I am asked to find the equation of the tangent line when x=3, I must find the y value for the expression how does one do that? When I plug in x=3 I can solve for y= 6-2y'

    but I don't know where to go from there.
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    Re: after implicitly differentiating an expression, find equation of tangent line at

    Plug x = 3 into your original equation \displaystyle \begin{align*} x^2 + y = x\,y \end{align*} to get the corresponding y value.
    Thanks from kingsolomonsgrave
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    Re: after implicitly differentiating an expression, find equation of tangent line at

    OH! of course, thanks!
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