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after implicitly differentiating an expression, find equation of tangent line at x=a

Attachment 25375

I differentiated $\displaystyle x^2+y=xy$ to get the above equation.

Then I am asked to find the equation of the tangent line when x=3, I must find the y value for the expression how does one do that? When I plug in x=3 I can solve for $\displaystyle y= 6-2y'$

but I don't know where to go from there.

Re: after implicitly differentiating an expression, find equation of tangent line at

Plug x = 3 into your original equation $\displaystyle \displaystyle \begin{align*} x^2 + y = x\,y \end{align*}$ to get the corresponding y value.

Re: after implicitly differentiating an expression, find equation of tangent line at