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after implicitly differentiating an expression, find equation of tangent line at x=a

Attachment 25375

I differentiated to get the above equation.

Then I am asked to find the equation of the tangent line when x=3, I must find the y value for the expression how does one do that? When I plug in x=3 I can solve for

but I don't know where to go from there.

Re: after implicitly differentiating an expression, find equation of tangent line at

Plug x = 3 into your original equation to get the corresponding y value.

Re: after implicitly differentiating an expression, find equation of tangent line at