Limit of sequence {b_n}/n --> b
This should be easy, but I missed a week of my real analysis class and the problem recommends using a theorem not in the text.
Let {bn} be a sequence in IR with the property that bn+1 − bn → b as
n → ∞. Prove that bn/n → b as n → ∞. [Hint: Use Theorem 3 from
class].
Re: Limit of sequence {b_n}/n --> b
Re: Limit of sequence {b_n}/n --> b
Thanks for the help, but I don't think that your answer works, or more precisely I don't think that it answers the question. I'm pretty sure that I need to show that the
bn/n → b as n → ∞
where the bn is a term of the ORIGINAL {bn} sequence.
My guess is that I'm going to need to start with the definition of a limit for a convergent sequence:
"A real number x is the limit of the sequence (xn) if the following condition holds:for each ε > 0, there exists a natural number N such that, for every http://upload.wikimedia.org/math/1/7...9574566b34.png, we have http://upload.wikimedia.org/math/0/1...3b40c5e581.png.In other words, for every measure of closeness ε, the sequence's terms are eventually that close to the limit. The sequence (xn) is said to converge to or tend to the limit x, written http://upload.wikimedia.org/math/4/6...96553475ef.png orhttp://upload.wikimedia.org/math/1/5...ca9eb2d60a.png."
I believe that theorem 3 is going to be a common analysis theorem, possibly one that is better known in some generalized form or when dealing with functions2nd +, however our text merely glosses over dealing with sequences.
Re: Limit of sequence {b_n}/n --> b
Quote:
Originally Posted by
mickyduu
Thanks for the help, but I don't think that your answer works, or more precisely I don't think that it answers the question. I'm pretty sure that I need to show that the
bn/n → b as n → ∞
Yes it does. PLease see my EDIT. There was a cut&paste error.
It proves that
so  \to b)