in limits for 1^∞ type of indeterminate form, the direct solution is e^{g(x)[f(x)-1]}
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Originally Posted by satyam in limits for 1^∞ type of indeterminate form, the direct solution is e^{g(x)[f(x)-1]} I am not sure what you mean by "direct solution" but you can convert the form so L'hosiptials rule can be used. If and then This is now in the form so you can apply L.H. Note the fraction could also be arrainged to get infinity over infinity
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