when taking the limit as x goes to negative infinity, and we divided by negative sqrt(x^2) why does the term 5x not become -5? the negative is associated only with the second term in the denominator but not the 5, why? also why is the denominator not divided by a negative?
Follow Math Help Forum on Facebook and Google+
This is what happens: Suppose then thus Suppose then Now (check it) the limit will be equal to 4
Perphas this also can help you: substituting for example in we get . Now, divide numerator by and denonimator by . What do you obtain? (substtitute now by )
View Tag Cloud