when taking the limit as x goes to negative infinity, and we divided by negative sqrt(x^2) why does the term 5x not become -5?
the negative is associated only with the second term in the denominator but not the 5, why?
also why is the denominator not divided by a negative?
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This is what happens:
Suppose then thus
Now (check it) the limit will be equal to 4
Perphas this also can help you: substituting for example in we get . Now, divide numerator by and denonimator by . What do you obtain? (substtitute now by )
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