1 Attachment(s)

limits at negative infinity

Attachment 25349

when taking the limit as x goes to negative infinity, and we divided by negative sqrt(x^2) why does the term 5x not become -5?

the negative is associated only with the second term in the denominator but not the 5, why?

also why is the denominator not divided by a negative?

Re: limits at negative infinity

This is what happens:

Suppose then thus

Suppose then

Now (check it) the limit will be equal to 4

Re: limits at negative infinity

Perphas this also can help you: substituting for example in we get . Now, divide numerator by and denonimator by . What do you obtain? (substtitute now by )