There may be a more elegant way, but I always do these in baby steps.Originally Posted by vish1987
Now, the first integral:
Use
Inserting the end limits:
The second integral is easy:
So we need to subtract. Finally:
.
-Dan
an some1 please help me with the following 2 question, i have attemped both but seem to come out with the correct answer:
1. ∫dx ∫(x-y)dy the 1st integral sign has the limits a and 0. the 2nd sign has the limits y1 and 0. where y1 = (a^2 -x^2)^0.5
for this ques the answer should be 0.
2. by changing the order of integration evaluate:
∫dx∫y^-1 sinycos(x/y)dy for the 1st integral sign, limits are 1 and 0. the 2nd sign has limits 1 and x.
answer: sin1(1-cos1)
The integral to be evaluated is:Originally Posted by vish1987
Which we may write:
where A is the region between the y-axis, and the lines x=1 and x=y,
and ds the the area element. This now may be written as:
,
which may be integrated to give:
RonL