Evaluate limit as x approaches 0 of ((sin(x)-x+(1/6)x^3)/(x^5)) HINT: Use the Maclaurin series representation of sin(x) I'm not sure how to go about doing this...
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$\displaystyle \sin{x} = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + ...$
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