<1> Lim ln(2x-1) / sin (pi)x

x->1

<2>Lim [((x+1)/ln(x+1)) -1/x)]

x->0

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- Mar 1st 2006, 06:07 AM #1

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- Mar 1st 2006, 06:57 AM #2

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Originally Posted by**bobby77**

As:

,

and

we need to use L'Hopital's rule to evaluate the limit so we need:

,

and:

.

Then L'Hopital's rule tells us that:

.

Finally checking with numerical experiments indicates that this is right.

RonL

- Mar 1st 2006, 07:31 AM #3

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