Here is intersection of plane z=3 with f(x,y):
Hey everyone,
I am having a bit of difficulty understanding a problem. It says: The trace of the graph of z = f(x,y) = on the plane z=3, is which of the following conic sections?
At first glance, the equation of z = is an elliptic paraboloid. However, if I plug-in z=3 into the equation, I get
= 3, which is an ellipse I believe. So, exactly how am I suppose to solve this problem. Am I already correct in assuming the answer is an ellipse? Or is my understanding of the problem incorrect.
Any help and feedback is greatly appreciated, thanks.