Results 1 to 2 of 2
Like Tree1Thanks
  • 1 Post By skeeter

Thread: Finding local minimum values

  1. #1
    Sep 2012
    United States

    Finding local minimum values

    I am given the function ln(x^4 + 27) I took the derivative I got (4x^3)/(x^4+27) I found the critical number which was 0. I made intervals of (-infinity,0) and (0,infinity)

    I found that the function was increasing on (0,infinty) and decreasing on (-infinty, 0) I found no local maxiumums. However I thought there would be a local minimum at x=0 but I'm wrong what is the local miniumum?
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    skeeter's Avatar
    Jun 2008
    North Texas

    Re: Finding local minimum values

    the function has no maximum, but an absolute minimum of $\displaystyle y = \ln(27)$ at $\displaystyle x = 0$ ... an absolute minimum is also a local minimum.
    Thanks from neontiger94
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 4
    Last Post: Mar 21st 2011, 01:23 AM
  2. Replies: 6
    Last Post: Jan 5th 2011, 02:34 AM
  3. local minimum and maximum values
    Posted in the Calculus Forum
    Replies: 2
    Last Post: Aug 16th 2010, 03:05 PM
  4. Replies: 0
    Last Post: Feb 23rd 2010, 09:40 AM
  5. Replies: 3
    Last Post: Nov 6th 2007, 12:22 PM

Search Tags

/mathhelpforum @mathhelpforum