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Math Help - differentiating y=tan(u*pi)

  1. #1
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    differentiating y=tan(u*pi)

    tan (u*pi)=sec^2(u)(pi) = pi*sec^2 (pi*x)

    i understand how the derivative would be sec^2u times pi, but how does that multiplication give

    pi*sec^2pi*x


    where did the x come from?


    sec^2u times pi[/tex] is equal to [tex]pi*sec^2 (pi*x) ?

    PS I tried wrapping this in [tex] but it came up with all kinds of errors for some reason, let me know if its too crappyly written and i'll find a way to re-write it (im out of time at the mo or I'd rewrite it now)
    Last edited by kingsolomonsgrave; October 17th 2012 at 10:26 AM.
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  2. #2
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    Re: differentiating y=tan(u*pi)

    differentiating y=tan(u*pi)-screen-shot-2012-10-17-2.26.52-pm.png

    this is a picture of the answer the question was

    y=tan pi x

    where did the second pi and x come from?
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  3. #3
    MHF Contributor MarkFL's Avatar
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    Re: differentiating y=tan(u*pi)

    \frac{d}{du}\left(\tan(\pi u) \right)=\sec^2(\pi u)\frac{d}{du}(\pi u)=\pi\sec^2(\pi u)
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  4. #4
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    Re: differentiating y=tan(u*pi)

    thanks! i see now, I was not including sec^2(pi*u), i was just multiplying by sec^2 of nothing
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