Based off of the pdf document "those who never learned to do epsilondelta." How do you solve for $\displaystyle |x-0|$ in the following $\displaystyle \lim_{x\to 0}\frac{1}{x^2-1}=1$. This is what I currently have: $\displaystyle \frac{|x^2|}{|x^2-1|}\leq \epsilon$