# limit

• Oct 16th 2012, 06:26 PM
arsenal12345
limit
lim 6x^2+2x+1/5x^2-3x+4
x-->

how do i solve the above questions ? can someone solve it and tell me and show me step by step please ?

thank you
• Oct 16th 2012, 06:32 PM
johnsomeone
Re: limit
$\lim_{x \to \infty} \frac{6x^2+2x+1}{5x^2-3x+4} = \lim_{x \to \infty} \frac{6+\frac{2}{x}+\frac{1}{x^2}}{5+ \frac{-3}{x}+\frac{4}{x^2}}\text{ ...that's from dividing top and bottom by } x^2.$