Could someone check my math?
$\displaystyle \int(3x+2)^2 dx$
From that I got the answer.
$\displaystyle 3x^3+6x^2+4x+C$
Is that correct? I used the sum rule, then I used the power rule to get this. Thanks for any feedback.
Could someone check my math?
$\displaystyle \int(3x+2)^2 dx$
From that I got the answer.
$\displaystyle 3x^3+6x^2+4x+C$
Is that correct? I used the sum rule, then I used the power rule to get this. Thanks for any feedback.
Another way to proceed is to let:
$\displaystyle u=3x+2\,\therefore\,du=3\,dx$ and we have:
$\displaystyle \frac{1}{3}\int u^2\,du=\frac{u^3}{9}+C=\frac{(3x+2)^3}{9}+C$
You can verify that this is equivalent to the form you gave.