How Do I solve this

Sin2πx [-1,1]

Yes continuous

Yes differentiable

f(-1) = f(1)

So now derive

2cos2πx = 0

How do I solve this? The answer in my book says +/- 1/4, +/- 3/4

How

Printable View

- Oct 15th 2012, 06:49 PMskinsdomination09How Do I solve this (using rolle's)?!?! (sin2pi*x) on -1,1 interval(TESTPREP PLZHELP)
How Do I solve this

Sin2πx [-1,1]

Yes continuous

Yes differentiable

f(-1) = f(1)

So now derive

2cos2πx = 0

How do I solve this? The answer in my book says +/- 1/4, +/- 3/4

How - Oct 15th 2012, 06:59 PMTheEmptySetRe: How Do I solve this (using rolle's)?!?! (sin2pi*x) on -1,1 interval(TESTPREP PLZH