How Do I solve this Sin2πx [-1,1] Yes continuous Yes differentiable f(-1) = f(1) So now derive 2cos2πx = 0 How do I solve this? The answer in my book says +/- 1/4, +/- 3/4 How
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Originally Posted by skinsdomination09 How Do I solve this Sin2πx [-1,1] Yes continuous Yes differentiable f(-1) = f(1) So now derive 2cos2πx = 0 How do I solve this? The answer in my book says +/- 1/4, +/- 3/4 How I am going to have to GUESS what the question is.... I am assuming that you are trying to find the points in where If so you need to solve the equation Taking the arccosine of both sides gives This will generate all of the solutions to the problem.
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