How Do I solve this
Sin2πx [-1,1]
Yes continuous
Yes differentiable
f(-1) = f(1)
So now derive
2cos2πx = 0
How do I solve this? The answer in my book says +/- 1/4, +/- 3/4
How
How Do I solve this
Sin2πx [-1,1]
Yes continuous
Yes differentiable
f(-1) = f(1)
So now derive
2cos2πx = 0
How do I solve this? The answer in my book says +/- 1/4, +/- 3/4
How