limit as x approaches pi/2 from the right side using l'Hospitals's Rule

I found that:

so I found the derivatives of them and I got:

I'm not sure on what I am doing wrong.

Re: limit as x approaches pi/2 from the right side using l'Hospitals's Rule

lim from right ->

Re: limit as x approaches pi/2 from the right side using l'Hospitals's Rule

Quote:

Originally Posted by

**amthomasjr**

I found that:

so I found the derivatives of them and I got:

I'm not sure on what I am doing wrong.

You haven't, technically, done **anything** wrong, except that, of course, because you **cannot** divide by 0, you cannot evaluate that final limit by simply setting . What you can do now is argue that, for x close to , but larger, sin(x) will be very close to 1 while cos(x) will be very close to 0 and **negative**. That gives the result that the limit is " " as MaxJasper said. I will add that " " is not a real number so that is just saying "the limit does not exist", in a particular way.

Re: limit as x approaches pi/2 from the right side using l'Hospitals's Rule