z=ycos(x-y)

at

(2,2,2)

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- October 15th 2012, 05:25 AMallstar2Find an equation of the tangent plane at the specified point
z=ycos(x-y)

at

(2,2,2) - October 15th 2012, 06:40 PMchiroRe: Find an equation of the tangent plane at the specified point
Hey allstar2.

Hint: You have z = f(x,y) so you have two derivatives: one with respect to x and one with respect to y. Can you find the expression for those derivatives? - October 18th 2012, 09:20 AMhollywoodRe: Find an equation of the tangent plane at the specified point
The partial derivatives give you two vectors in the tangent plane. Then the cross product of these vectors is the normal vector you need to get the equation for the tangent plane.

- Hollywood