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Math Help - Indefinite Integral

  1. #1
    Newbie Assassin0071's Avatar
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    Indefinite Integral

    I'm working out a problem and reached an integral of the following form. I'm not entirely sure how to evaluate it. I tried substitution and parts but ended up nowhere so far. Any help would be greatly apperciated.

    \int\sqrt{\frac{r}{hr+u}}\,dr

    Where u and h are constants.
    Last edited by Assassin0071; October 13th 2012 at 08:02 PM.
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  2. #2
    Senior Member MaxJasper's Avatar
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    Lightbulb Re: Indefinite Integral

    A solution most likey looks like:

    \frac{1}{h^{3/2} \sqrt{r}}\sqrt{\frac{r}{h r+u}} \left(\sqrt{h} \sqrt{r} (h r+u)-u \sqrt{h r+u} \text{Log}\left[h \sqrt{r}+\sqrt{h} \sqrt{h r+u}\right]\right)
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    Re: Indefinite Integral

    Thanks, but the problem is I'm not even sure how to start getting to that solution.
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  4. #4
    Senior Member MaxJasper's Avatar
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    Re: Indefinite Integral

    Is u or h a function of r?
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    Re: Indefinite Integral

    Sorry I should have mentioned that u and h are constants.
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