I was working on a problem and I just can not figure out how to accomplish what it is asking. Attached is the problem and figure.

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- Oct 13th 2012, 02:15 PMChip7723Showing the continuity of a Function and its derv.
I was working on a problem and I just can not figure out how to accomplish what it is asking. Attached is the problem and figure.

- Oct 13th 2012, 03:09 PMMathoManRe: Showing the continuity of a Function and its derv.
$\displaystyle f'(x)\lim\limits_{h\to 0}\frac{f(x+h)-f(x)}{h}\Rightarrow f'(0)=\lim\limits_{h\to 0}\frac{f(0+h)-f(0)}{h}$

$\displaystyle f'(0)=\lim\limits_{h\to 0}\frac{f(h)-f(0)}{h}=\frac{h^2\sin \frac{1}{h}-0}{h}=$

$\displaystyle \lim\limits_{h\to 0}h\sin \frac{1}{h}= \lim\limits_{h\to 0}\frac{\sin \frac{1}{h}}{\frac{1}{h}}=0. $

So if you use that extension of the function f, you can say that at x=0, f'(0)=0 and the interpretation is that the tangent line would be the x-axis.

$\displaystyle f'(x)=\left\{ \begin{array}{rl} \left(x^2\sin\frac{1}{x}\right)', & \forall x \neq 0,\\

0, & \text(if ) x=0. \end{array}\right.$

No you have to prove that h it is continuous.