# integration

• Oct 13th 2007, 04:32 PM
kittycat
integration
The integral from 0 to 1 of (1+2t)/(1+t^2) dt.

Thank you very much.
• Oct 13th 2007, 04:40 PM
galactus
$\int\frac{1+2t}{1+t^{2}}dt=\int\frac{2t}{t^{2}+1}d t+\int\frac{1}{t^{2}+1}dt$

For the first half, let $u=t^{2}, \;\ du=2tdt$

The other part you should recognize as arctan.