How do you find an equation of the target line to the at the given point : y=(1+x)cosx at the point 0,1.
I think you use product rule and then plug it into y=mx+b but i cant get right answer
Yes you use the product rule
This gives
$\displaystyle y'(x)=-(1+x)\sin(x)+\cos(x)$
Now we can find the slope at the point (0,1)
$\displaystyle m=y'(0)=-(1+0)\sin(0)+\cos(0)=1$
Since we know the y intercept (the point (0,1) )
We know b=1
This gives
$\displaystyle y=1(x)+1 \implies y=x+1$
P.S where in Oregon are you from? I do miss Corvallis and Portland quite alot! Go Beavers!!