tangent line or something.
How do you find an equation of the target line to the at the given point : y=(1+x)cosx at the point 0,1.
I think you use product rule and then plug it into y=mx+b but i cant get right answer 

Re: tangent line or something.
Tangent: y  y(0)=y'(0)*(xx0)
{x0,y(x0)} = {0,1}
y'(x) = cos(x)  (1+x)*sin(x)
Re: tangent line or something.
Re: tangent line or something.
"the derivative is the slope of the tangent line"
That's perhaps the single most important and commonly used phrase in Calculus I.