• Oct 11th 2012, 10:03 PM
LanieH
I need to solve this equation for 'B'. I am having trouble rearranging the equation to achieve a 'B=' answer. Can someone help me rearrange this equation to solve for B?

0=((DCRMg) - (DCRMgAl)) ∗ e^(-B∗((ρMg)+(ρAl)))+ ((DCRMgAl )- (DCRAl ))∗e^(-2∗B∗(ρMg) )+((DCRAl) - (DCRMg)) e^(-B∗((ρMg)+(ρMgAl)))
• Oct 11th 2012, 10:07 PM
chiro
Hey LanieH.

Can you show us what you have tried? You might want to start off by moving the 2nd and later terms to the LHS and then taking logarithms.
• Oct 12th 2012, 05:00 AM
LanieH
Hi Chiro.
I have not even attempted to solve this. I do not know how to solve an equation like this for B. Are you able to give it a try? Do you know of anyone who may be able to solve this?
• Oct 12th 2012, 09:07 AM
MaxJasper
Is Al one variable or it is A*L
• Oct 12th 2012, 09:28 AM
MaxJasper
Quote:

Originally Posted by LanieH
I need to solve this equation for 'B'. I am having trouble rearranging the equation to achieve a 'B=' answer. Can someone help me rearrange this equation to solve for B?

0=((DCRMg) - (DCRMgAl)) ∗ e^(-B∗((ρMg)+(ρAl)))+ ((DCRMgAl )- (DCRAl ))∗e^(-2∗B∗(ρMg) )+((DCRAl) - (DCRMg)) e^(-B∗((ρMg)+(ρMgAl)))

D|C|R=0

This eq simplifies to:

$\displaystyle m g(1- a l) * e^{-b \rho ( m g+ a l)}+ a l( m g-1)*e^{-2b \rho m g}+( a l- m g) *e^{-b \rho m g( 1+ a l)}=0$

If you have numerical values of the parameters then b can be evaluated! otherwise I can't see a closed form solution(Angry)