1. ## Limit question

Hello,

I think the question is simple but not sure if this would be correct. I have a limit that is:
lim x2-25
______
x->2 sqrt (2x+6) -4

Now the bottom would be root 10 - 4, so I don't think I need to multiply it by root 10 +4 to get rid of it so is that fine?
x could not be 5

Thanks!

2. ## Re: Limit question

Correct, you dont need to multiply through by the conjugate.

3. ## Re: Limit question

Thanks... I felt like that was a trick question or something because normally in other questions that is what you do. So you don't always have to conjugate then

4. ## Re: Limit question

No, in your case substituting the value is fine.

5. ## Re: Limit question

Originally Posted by funnybabe
Hello,

I think the question is simple but not sure if this would be correct. I have a limit that is:
lim x2-25
______
x->2 sqrt (2x+6) -4

Now the bottom would be root 10 - 4, so I don't think I need to multiply it by root 10 +4 to get rid of it so is that fine?
x could not be 5

Thanks!
If a function is continuous at the point you are making the function approach, then the limit is equal to the function value at that point.