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Math Help - Limit question

  1. #1
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    Limit question

    Hello,

    I think the question is simple but not sure if this would be correct. I have a limit that is:
    lim x2-25
    ______
    x->2 sqrt (2x+6) -4

    Now the bottom would be root 10 - 4, so I don't think I need to multiply it by root 10 +4 to get rid of it so is that fine?
    x could not be 5

    Thanks!
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  2. #2
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    Re: Limit question

    Correct, you dont need to multiply through by the conjugate.
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  3. #3
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    Re: Limit question

    Thanks... I felt like that was a trick question or something because normally in other questions that is what you do. So you don't always have to conjugate then
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  4. #4
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    Re: Limit question

    No, in your case substituting the value is fine.
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  5. #5
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    Re: Limit question

    Quote Originally Posted by funnybabe View Post
    Hello,

    I think the question is simple but not sure if this would be correct. I have a limit that is:
    lim x2-25
    ______
    x->2 sqrt (2x+6) -4

    Now the bottom would be root 10 - 4, so I don't think I need to multiply it by root 10 +4 to get rid of it so is that fine?
    x could not be 5

    Thanks!
    If a function is continuous at the point you are making the function approach, then the limit is equal to the function value at that point.
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