your algebra needs work ...
, now take the derivative.
, only the x has a negative exponent
I have 2 problems I was confused with.
1. f(x)=(2x^{2}-3x+1)/x
2. f(x)=x^{4/5 }This is what I did for the first one:
I moved the x up, which turns into 2x^{2}-3x+1+x^{-1}
Then I multipled the coefficient by the exponents, and subtracted 1 from the exponent: 4x-3+1+x^{-2}
But I was wondering, what do you do for the 1 here?
And for the second one:
Same thing, multipled exponent into coefficient: (4/5)x^{-1/5}
Then 1/(4/5x^{5})
Then I got lost here... the answer in the book is: 4/(5x^{1/5})
It looks like the denominator just had the exponent switched into the positive, is that the right way to move it though?